How do you solve #x^ { 2} + 7= 23#?

1 Answer
smendyka
Jan 17, 2018

See a solution process below:

Explanation:

First, subtract #color(red)(7)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#x^2 + 7 - color(red)(7) = 23 - color(red)(7)#

#x^2 + 0 = 16#

#x^2 = 16#

Now, take the square root of each side of the equation to solve for #x# while keeping the equation balanced. Remember, the square root of a number provides both a positive and negative result.

#sqrt(x^2) = +-sqrt(16)#

#x = +-4#

#x = {-4, 4}#

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