How do you solve #x^2 - 8x + 16 = 16#?

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Answer 1 · 2015-12-23T17:05:05

The solutions are:
#color(blue)(x=0,x=8#

#x^2-8x+16=16#

#x^2-8x+16-16=0#

#x^2-8x+0=0#

#x^2-8x=0#

#x(x-8)=0#

Equating the factors to #0#:

#x=0#

#x-8=0#
#x=8#

The solutions are:
#color(blue)(x=0,x=8#