How do you solve #x^2+8x+7=0# by factoring?
1 Answer
Oct 29, 2017
Explanation:
Separate the middle term into two terms which will match the first and third terms:
#x^2 + 8x + 7 = 0#
#x^2 + x + 7x + 7 = 0#
#(x^2+x)+(7x+7) = 0#
#x(x+1) + 7(x+1) = 0#
#(x+7)(x+1) = 0#
Therefore:
#x+7 = 0 " " or " " x + 1 = 0#
#x = -7 " " or " " x = -1#
Final Answer
