How do you solve #x^2 - x - 2 ≥ 0#?
1 Answer
Jun 15, 2018
Explanation:
#"factor the quadratic"#
#(x-2)(x+1)>=0#
#"solve "(x-2)(x+1)=0#
#x=-1" or "x=2larrcolor(red)"x-intercepts"#
#"since "a>0" then graph is a minimum "uuu#
#"for "x^2-x-2>=0#
#x<= -1" or "x>=2#
#(-oo,-1]uu[2,oo)larrcolor(blue)"in interval notation"#
graph{x^2-x-2 [-10, 10, -5, 5]}
