How do you solve #(x+2)/(x-2)=4/8#?

1 Answer
Dec 17, 2016

Answer:

#x = -6#

Explanation:

First, we each side of the equation by a common denominator (in this case #8(x - 2)#) to eliminate the fraction and keep the equation balanced:

#8(x - 2) (x + 2)/(x - 2) = 8(x - 2) 4/8#

#8cancel((x - 2)) (x + 2)/cancel((x - 2)) = cancel(8)(x - 2) 4/cancel(8)#

#8(x + 2) = 4(x - 2)#

Now we can expand the terms in parenthesis on each side of the equation:

#8x + 16 = 4x - 8#

Next we can isolate the #x# terms on one side of the equation and the constants on the other side of the equation while keeping the equation balanced:

#8x + 16 - 16 - 4x = 4x - 8 - 16 - 4x#

#8x + 0 - 4x = 0 - 24#

#8x - 4x = -24#

#4x = -24#

Finally, we can solve for #x# while keeping the equation balanced:

#(4x)/4 = (-24)/4#

#(cancel(4)x)/cancel(4) = -6#

#x = -6#