How do you solve #x / 2 - y / 3 = 5/6# and #x / 5 - y / 4 = 29 / 10# using substitution?
Before we can even think of solving, let's change the equations into a more user-friendly form!.
Multiply each by the LCM of the denominators to get rid of the fractions.
Make one of the variables in one equation the subject.
(one is not really easier than the other to substitute.)
Check these values in the second equation to verify.