How do you solve x−2y=−1 and 2x−y=4 using substitution?

1 Answer
Jumbotron
Jun 1, 2018

x=3and=2

Explanation:

x−2y=−1−−−eqn1

2x−y=4−−−eqn2

Using Substitution Method..

From eqn1

x−2y=−1−−−eqn1

Making x the subject of formula;

x−2y=−1

x=−1+2y

x=2y−1−−−eqn3

Substitute eqn3 into eqn2

2x−y=4−−−eqn2

2(2y−1)−y=4

4y−2−y=4

4y−y−2=4

3y−2=4

3y=4+2

3y=6

y=63

y=2

Substituting the value of y into eqn3

x=2y−1−−−eqn3

x=2(2)−1

x=4−1

x=3

Therefore;

x=3and=2

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