How do you solve $x-2y<8$ and $2x-3y<=6$ ?

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Answer 1 · 2018-02-19T13:58:30

See below.

We have

${(x-2y=8-lambda_1^2),(2x-3y=6-lambda_2^2):}$

with ${lambda_1 ne 0, lambda_2} in RR$

Now solving for ${x,y}$ we get at

${(x=3lambda_1^2-2lambda_2^2-12),(y=2lambda_1^2-lambda_2^2-10):}$

which means that the solution is the union set for all ${lambda_1 ne 0, lambda_2} in RR$

How do you solve x-2y<8x-2y<8 and 2x-3y<=62x-3y<=6?