How do you solve #(x+3)/3=(10+4)/4#?

1 Answer
Aug 22, 2017

See a solution process below:

Explanation:

First, we can simplify the right side of the equation:

#(x + 3)/3 = 14/4#

#(x + 3)/3 = (2 xx 7)/(2 xx 2)#

#(x + 3)/3 = (color(red)(cancel(color(black)(2))) xx 7)/(color(red)(cancel(color(black)(2))) xx 2)#

#(x + 3)/3 = 7/2#

Next, we can multiply each side of the equation by #color(red)(3)# to eliminate the fraction on the left side of the equation while keeping the equation balanced:

#color(red)(3)(x + 3)/3 = color(red)(3) xx 7/2#

#cancel(color(red)(3))(x + 3)/color(red)(cancel(color(black)(3))) = 21/2#

#x + 3 = 21/2#

Now, we can subtract #color(red)(3)# from each side of the equation to solve for #x# while keeping the equation balanced:

#x + 3 - color(red)(3) = 21/2 - color(red)(3)#

#x + 0 = 21/2 - (2/2 xx color(red)(3))#

#x = 21/2 - 6/2#

#x = (21 - 6)/2#

#x = 15/2#