How do you solve #(x-3)/4=2#?

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Answer 1 · 2016-09-07T19:57:55

#x = 11#

#(x-3)/4 = 2 " "larr# isolate the numerator with x.

Multiply both sides by 4

#(cancel4xx(x - 3))/cancel4= 2xx4" "larr# isolate x.

#x-3 = 8#

Add 3 to both sides.

#x-3+3 = 8+3#

#x = 11#