How do you solve $x - 3 y = - 2, - 2 x + 5 y = - 7$ $x-3y=-2, -2x+5y=-7$ ?

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Answer 1 · 2017-01-02T14:34:15

$y = 11, x = 31$ $y=11,x=31$

$x - 3 y = - 2, - 2 x + 5 y = - 7$ $x-3y=-2, -2x+5y=-7$

$x - 3 y = - 2$ $x-3y=-2$ $.................1$

$-2x+5y=-7.............2$

$2x-6y=-4$ .....................3 $=1 xx 2$

$-y=-11$ ............................ $=2+3$

$y=11$

$5x-15y=-10$ ....................4 $=1xx5$

$-6x+15y=-21.............5$ = $2xx3$

$-x=-31$ ...............................= $4+5$

$x=31$

substitute $y=11,x=31$ in 1

$31-3(11)=-2$

$31-33=-2$

$-2=-2$

How do you solve x-3y=-2, -2x+5y=-7x−3y=−2,−2x+5y=−7x-3y=-2, -2x+5y=-7?