How do you solve #-x - 4= - 13x - 100#?

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Answer 1 · 2017-08-01T00:45:19

See a solution process below:

Step 1) Add #color(red)(4)# and #color(blue)(13x)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#color(blue)(13x) - x - 4 + color(red)(4) = color(blue)(13x) - 13x - 100 + color(red)(4)#

#color(blue)(13x) - 1x - 0 = 0 - 96#

#(color(blue)(13) - 1)x = -96#

#12x = -96#

Step 2) Divide each side of the equation by #color(red)(12)# to solve for #x# while keeping the equation balanced:

#(12x)/color(red)(12) = -96/color(red)(12)#

#(color(red)(cancel(color(black)(12)))x)/cancel(color(red)(12)) = -8#

#x = -8#