How do you solve #x/.4 = 2x+1.2#?

1 Answer
Feb 19, 2017

See the entire solution process below:

Explanation:

First, multiply each side of the equation by #color(red)(0.4)# to eliminate the fraction while keeping the equation balanced:

#color(red)(0.4) xx x/0.4 = color(red)(0.4)(2x + 1.2)#

#cancel(color(red)(0.4)) xx x/color(red)(cancel(color(black)(0.4))) = (color(red)(0.4) xx 2x) + (color(red)(0.4) xx 1.2)#

#x = 0.8x + 0.48#

Next, subtract #color(red)(0.8x)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#x - color(red)(0.8x) = 0.8x + 0.48 - color(red)(0.8x)#

#1x - color(red)(0.8x) = 0.8x - color(red)(0.8x) + 0.48#

#(1 - 0.8)x = 0 + 0.48#

#0.2x = 0.48#

Now, divide each side of the equation by #color(red)(0.2)# to solve for #x# while keeping the equation balanced:

#(0.2x)/color(red)(0.2) = 0.48/color(red)(0.2)#

#(color(red)(cancel(color(black)(0.2)))x)/cancel(color(red)(0.2)) = 2.4#

#x = 2.4#