How do you solve #x/5 = 12/20#?

1 Answer
EZ as pi
Jul 7, 2016

#x = 3#

Explanation:

Try to isolate #x#on the left. Multiplying both sides of the equation by 5 will allow to cancel the 5 on the left. Finding #x# is then a simple computation.

#(5 xx x)/5 = (5 xx 12)/20#

#(cancel5 xx x)/cancel5 = (5 xx 12)/20#

#x = 3#

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