# How do you solve x-5y=6, 2x+3y=12 using substitution?

Mar 2, 2018

$x = 6$
$y = 0$

#### Explanation:

$x = 5 y + 6$

$2 \left(5 y + 6\right) + 3 y = 12$

$10 y + 12 + 3 y = 12$

$13 y + 12 = 12$

$13 y = 0$

$y = 0$

$x - 5 \left(0\right) = 6$

$x = 6$

By the way, here's what the graph would kind of look like:
graph{(y)^2-(x-6)^2=0 [-5, 10, -5, 5]} If you don't get it then just ignore it.