How do you solve #x- 6= - 2x + 18#?

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Answer 1 · 2016-11-30T22:02:15

#x = 8#

First, perform the necessary mathematics to isolate the #x# terms on one side of the equation and the constants on the other side of the equation:

#x - 6 + 2x + 6 = -2x + 18 + 2x + 6#

#x + 2x - 6 + 6 = -2x + 2x + 18 + 6#

#x + 2x - 0 = 0 + 18 + 6#

#3x = 24#

Next divide each side of the equation by #3# to solve for #x# while keeping the equation balanced:

#(3x)/3 = 24/3#

#(cancel(3)x)/cancel(3) = 8#

#x = 8#