How do you solve #(x - 6) ( x - 8) = - 1#?
1 Answer
Mar 22, 2018
x = 7
expand the left side before bringing the right side over
Explanation:
(x-6)(x-8) = -1
x^2 - 6x - 8x + 48 = -1
x^2 - 14x + 49 = 0
(x-7)(x-7)=0
x = 7
