How do you solve #x -7y=13# for #y#?

2 Answers
Apr 28, 2018

#y = (x-13)/7#

Explanation:

To solve for #y#, rearrange the current equation so that #y# is by itself on one side of the #=# sign.

#x - 7y = 13#

#x = 13 + 7y#

#x - 13 = 7y#

#(x-13)/7 = y#

So #y# is equivalent to #(x-13)/7#

Apr 28, 2018

#y=-1/7(13-x)#

Explanation:

#"leave - 7y on the left and all other terms on the right"#

#"subtract x from both sides"#

#cancel(x)cancel(-x)-7y=13-x#

#rArr-7y=13-x#

#"divide both sides by "-7#

#(cancel(-7) y)/cancel(-7)=(13-x)/-7#

#rArry=-1/7(13-x)#