How do you solve #( x - 8) ^ { 2} - 6= 43# for # x#?

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Answer 1 · 2017-03-13T19:59:38

The answers to this quadratic equation would be 1 and 15.

Start off by adding 6 to both sides.

#(x-8)^2-6=43# #-># #(x-8)^2-6+6=43+6# #-># #(x-8)^2=49#

After that, take the square root from both sides of the equation:

#sqrt ((x-8)^2)=sqrt 49#

This will leave you with #x-8= +-7# (the #+-# is used in this case because the square root of a number includes both a negative and positive answer).

Finally, the answer(s) are 1 #-># #8-7# and #15# #-># #8+5#

Hope this helps! :-)