How do you solve x-y=0 and 12x-5y=-21? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Don't Memorise Oct 14, 2015 The solution is #color(blue)(x=-3,y=-3# Explanation: #x-y=0# #x=color(blue)(y#......equation #1# #12x-5y=-21#....equation #2# Substituting #1# in #2# #12x-5y=-21# #12* (color(blue)(y))-5y=-21# #12y-5y=-21# #7y=-21# #y=-21/7# #color(blue)(y=-3# And since #x=y# #color(blue)(x=-3# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 1914 views around the world You can reuse this answer Creative Commons License