Question

How do you solve `y= 12( \frac { 2} { 9} ) ^ { x } - 3`?

Answer 1

`y=2^x/9^x-3`

Explanation:

`y=12(2/9)^x-3`

`:.y=24^x/108^x-3`

`:.y=cancel(24^x)^6/1 xx 1/cancel108^27-3`

`:.y=6^x/27^x-3`

`:.y=2^x/9^x-3`