# How do you solve y = (2/3)x – 1 and y = -x + 4 using substitution?

Jun 14, 2016

$x = 3 , y = 1.$

#### Explanation:

We substitute the value of y from first eqn. into the second eqn., to get,
$\left(\frac{2}{3}\right) x - 1 = - x + 4.$
$\therefore \left(\frac{2}{3}\right) x + x = 4 + 1.$
$\therefore \frac{2 x + 3 x}{3} = 5.$
$\therefore 5 \frac{x}{3} = 5$
$\therefore x = 5 \cdot \left(\frac{3}{5}\right) = 3.$

To get y, we use the second eqn.
$y = - x + 4 = - 3 + 4 = 1.$

The soln. is $x = 3 , y = 1.$