How do you solve $y=-3x+4$ and $-6x-2y=-8$ using substitution?

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Answer 1 · 2016-06-26T05:22:13

The two equations are the same. They represent the same line.
There are innumerable number of solutions to these system of equations.

Given -

$y=-3x+4$ ------------------(1)
$-6x-2y=-8$ ----------------(2)

Solve the second equation for $y$

$-2y=6x-8$
$y=6 /(-2)x-(8/(-2))$
$y=-3x+4$

The two equations are the same. They represent the same line.
There are innumerable number of solutions to these system of equations.

How do you solve y=-3x+4y=-3x+4 and -6x-2y=-8 -6x-2y=-8 using substitution?