How do you solve #y=3x# and #x+y=8# using substitution?

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Answer 1 · 2016-04-06T12:30:47

The solution for the system of equations is:
#color (green)(x=2)#

# color(green)(y =6) #

#color(green)(y= 3 x # ...............equation #(1)#
#x + y = 8# ........equation #(2)#

Substituting equation #1# in #2 : #

#x + y = 8#

#x + color(green)(3 x) = 8#

#4x = 8#

#x = 8 /4 = 2#

#color (green)(x=2)#

Substituting the value of #x# in equation #1# to find #y#:
#y= 3 x #

#y= 3 * color(green)(2) #

# color(green)(y =6) #