How do you solve #y/6+3=-11#?

1 Answer
jk.13 · Jensen Z
Mar 15, 2018

#y=-84#

Explanation:

The first step would be to eliminate the fraction, so to do that you would multiply the WHOLE equation by #6# (because #6# is the denominator of the fraction). Then, you would get

#y+18=-66#

To isolate the variable, you would subtract #18# from both sides, leaving you with

#y=-84#

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