# How do you solve #y = -x + 5# and #2x - 3y = -6# using substitution?

##### 1 Answer

#### Answer:

#### Explanation:

As given by the first equation, we see that

#2x-3color(red)y=-6" "=>" "2x-3(color(red)(-x+5))=-6#

When distributing

#-3(color(blue)-xcolor(blue)+5)=color(green)+3xcolor(green)-15#

So, we have

#2x+3x-15=-6#

#5x-15=-6#

#5x=9#

#color(purple)(x=9/5#

With this, we can plug this value for

#y=-color(purple)x+5" "=>" "y=-color(purple)(9/5)+5#

Find a common denominator:

#y=-9/5+25/5#

#color(brown)(y=16/5)#

Since we have