# How do you solve y = x² and 1 + y = 2x?

$x = 1$

#### Explanation:

$y = {x}^{2}$ (1)
$y = 2 x - 1$ (2)

Subtracting (1) - (2):

$0 = {x}^{2} - 2 x + 1$

${x}_{1} = {x}_{2} = 1$