How do you subtract #1/ a - 2/ a ^ { 2} - 3/ a ^ { 2} #?

1 Answer
Jim G.
Nov 28, 2016

#(a-5)/a^2#

Explanation:

2 of the fractions have a denominator of #a^2.# Before subtracting the 3 fractions we require them all at have a denominator of #a^2#

This can be achieved by multiplying #1/a" by " 1 " in the form " a/a#

#rArr1/axxa/a=a/a^2#

#rArra/a^2-2/a^2-3/a^2=(a-2-3)/a^2=(a-5)/a^2#

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