How do you subtract #1/ a - 2/ a ^ { 2} - 3/ a ^ { 2} #?
1 Answer
Nov 28, 2016
Explanation:
2 of the fractions have a denominator of
#a^2.# Before subtracting the 3 fractions we require them all at have a denominator of#a^2# This can be achieved by multiplying
#1/a" by " 1 " in the form " a/a#
#rArr1/axxa/a=a/a^2#
#rArra/a^2-2/a^2-3/a^2=(a-2-3)/a^2=(a-5)/a^2#
