# How do you subtract 37\frac { 4} { 15}- 26\frac { 5} { 9}?

$10 \frac{32}{45}$

#### Explanation:

Let's first change these to improper fractions:

$\frac{559}{15} - \frac{239}{9}$

The common denominator is $5 \times 3 \times 3 = 45$:

$\frac{559}{15} \left(\frac{3}{3}\right) - \frac{239}{9} \left(\frac{5}{5}\right)$

$\frac{1677}{45} - \frac{1195}{45} = \frac{482}{45} = 10 \frac{32}{45}$