How do you subtract #(7x+ 2)# from #(7x^2+4x+7)#?

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Answer 1 · 2017-09-14T13:04:10

See a solution process below:

First, we can write the expression as:

#(7x^2 + 4x + 7) - (7x + 2)#

Next, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

#7x^2 + 4x + 7 - 7x - 2#

Then, group like terms:

#7x^2 + 4x - 7x + 7 - 2#

Now, combine like terms:

#7x^2 + (4 - 7)x + (7 - 2)#

#7x^2 + (-3)x + 5#

#7x^2 - 3x + 5#