# How do you subtract #9/(x-2)-5/(x+4)#?

##### 1 Answer

Sep 14, 2016

#### Explanation:

To subtract fractions you need a common denominator, so let's use

#9/(x-2)-5/(x+4) = (9(x+4))/((x-2)(x+4))-(5(x-2))/((x-2)(x+4))#

#color(white)(9/(x-2)-5/(x+4)) = (9(x+4)-5(x-2))/((x-2)(x+4))#

#color(white)(9/(x-2)-5/(x+4)) = (9x+36-5x+10)/((x-2)(x+4))#

#color(white)(9/(x-2)-5/(x+4)) = (4x+46)/((x-2)(x+4))#

#color(white)(9/(x-2)-5/(x+4)) = (2(x+23))/((x-2)(x+4))#