How do you subtract #9/( y + 1) - 3/ ( 4y + 4)#?

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Answer 1 · 2017-11-25T18:08:22

In order to subtract, they need to have the same base, so you need to multiply the sides with the opposite’s base

#(9/(y+1))*(4y+4)# -

#(3/(4y+4))*(y+1))#

=

#(36y+36)/((y+1)(4y+4)) - (3y+3)/((y+1)(4y+4))#

Now you can subtract since they have the same bases

#(33y-33)/((y+1)(4y+4)) #