How do you subtract #\frac { 12n ^ { 3} + 5n } { n ^ { 5} } - \frac { 8n ^ { 3} + 2n ^ { 2} - 4n } { n ^ { 5} }#?

1 Answer
smendyka
Nov 2, 2016

#(4n^3 - 2n^2 +n)/n^5#

Explanation:

Because both fractions have the same denominator (#n^5#) you can combine terms in the numerator and keep the denominator the same:

#(12n^3 - 8n^3 - 2n^2 + 5n - 4n)/n^5#

#(4n^3 - 2n^2 +n)/n^5#

Would can be further simplified to:

#(n*(4n^2 - 2n + 1))/(n*n^4)#

#(4n^2 - 2n + 1)/n^4#

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