How do you subtract #\frac { 17} { 21} - \frac { 4} { 6}#?

2 Answers

#1/7# find a common denominator subtract the numerators and divide out any common factors.

Explanation:

21 can be factored into #7xx3#
6 can be factored into #2 xx 3#

7 and 2 are the uncommon factors

multiply #17/21 xx 2/2 = 34/42#

multiply #4/6 xx 7/7 = 28/42# subtract gives

#=(34-28)/42= 6/42 = 1/7#

Note :
In case you noticed that #4/6=2/3#:

#17/21-2/3xx7/7=17/21-14/21=3/21=1/7#

Nov 18, 2016

#17/21-4/6=1/7#

Explanation:

A fraction structure is #("count")/("size indicator")->("numerator")/("denominator")#

You can not directly add or subtract the 'counts' unless the 'size indicators' are the same.

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Multiply by 1 and you do not change the value. However 1 comes in many forms. So you can change the way a fraction looks without changing its value.

#color(green)([17/21color(red)(xx1)]-[4/6color(red)(xx1)])" "->" "color(green)([17/21color(red)(xx2/2)]-[4/6color(red)(xx7/7)])#

#" "[ 34/42] - [28/42]#

#" "=6/42 -= (6-:6)/(42-:6) = 1/7#