How do you subtract #\frac { 4z - 8} { 4z } - \frac { 2z - 7} { 5z }#?

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Answer 1 · 2018-03-06T07:05:40

#=>color(red)((3(z - 1)) / (5z)#

#(4z - 8) / (4z) - (2z - 7) / (5z)#

Taking LCM as 20z,

#=> ((5(4z - 8)) - (4 (2z - 7))) / (20z)#

#=> (20z - 40 - 8z + 28) / (20z)# Removing braces,

#=> (20z - 8z -40 + 28) / (20z)# Rearranging terms.

#=> (cancel(12z)^color(brown)(3z)- cancel(12)^color(brown)3 ) / (cancel(20z)^color(brown)(5z))# canceling common coefficients.

#=>(3(z - 1)) / (5z)#