How do you subtract #\frac { 6a ^ { 2} - 7a + 8} { 2a - 1} - \frac { a ^ { 2} - 4a + 6} { 2a - 1}#?

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Answer 1 · 2017-05-15T06:41:14

Since the denominators are the same you can get right to subtracting.

There is a minus sign splitting the two parts of the equation

Multiply the second half of the equation by -1 because that negative applies to ALL terms

#(-1*(a^2 - 4a +6))/(2a-1)#

That will then result in

#(-a^2 + 4a -6)#

Then combine the equation under one denominator like so

#(6a^2-7a+8-a^2+4a-6)/(2a -1)#

Simplify

#(5a^2-3a+2)/(2a-1)#

Since the numerator cannot be simplified further the final answer is

#(5a^2-3a+2)/(2a-1)#