How do you subtract #\frac { 9- 4y } { 3y } - \frac { 6- y } { 3y }#?

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Answer 1 · 2017-03-22T03:12:23

The denominators are already the same, so subtract the numerators and then simplify to get.

# ( 1- y)/ y #

# (9 -4y - ( 6 - y ))/(3y)#

#= (9 -4y - 6 + y )/(3y)#

#= (9 -6 - 4y + y )/(3y)#

#=(3 -3y)/(3y) #

#=( 3 - 3y)/ (3y)" "# Factor 3 out of the numerator

# =(3 ( 1-y ) )/(3 xx y)" "# The 3 in the numerator and the 3 in the #color(white)(......................)#denominator can be cancelled, leaving

#= ( 1- y)/ y #