How do you subtract #(x-4)-(x^2+3)# and write the resulting polynomial in standard form?

1 Answer
Alan N.
Jun 5, 2017

#-x^2+x-7#

Explanation:

The standard form for a quadratic is: #ax^2+bx+c#

In this case we have: #(x-4)-(x^2+3)#

#= x-4-x^2-3# (distributing the #-# over the second bracketed term)

#= -x^2+x-7#

(i.e. #a=-1, b=+1, c=-7#

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