How do you take the derivative of $tan^2(4x)$ ?

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Answer 1 · 2015-07-02T22:07:49

$(d[tan^2(4x)])/(dx)=8sec^2(4x)tan(4x)$

$(d[tan^2(4x)])/(dx)=2sec^2(4x).tan(4x)xxd((4x))/dx$

$=2sec^2(4x).tan(4x)xx4$

$=8sec^2(4x)tan(4x)$

How do you take the derivative of tan^2(4x) tan^2(4x)?