Question

How do you take the derivative of `(tan(8x))^2`?

Answer 1

`dy/dx=16tan(8x)sec^2(8x)`

Explanation:

Use the Chain Rule a couple times, along with the fact that `d/dx(tan(x))=sec^2(x)`:

`d/dx(tan^2(8x))=2tan(8x)*d/dx(tan(8x))`

`=2tan(8x)*sec^2(8x)*d/dx(8x)`

`=16tan(8x)sec^2(8x)`