How do you translate word phrases to algebraic expressions: a number squared plus two times the number less 7 is equal to zero?

1 Answer
Jul 6, 2016

Answer:

#x^2 + 2(x-7) = 0#

Explanation:

Let's break this down.

a number: this means "any number", so we can substitute that with a variable, #x#

squared: this means squaring the number, or multiplying it by itself (written as #x^2#; #x# squared)

two times the number: we've already established the number is #x#, and two times that number would be #2x# (since we are multiplying it by two, hence "times")

the number less 7: this looks like subtraction (a number less seven would be #x - 7#

For the parts I left out, I thought they would be easy to comprehend. If you did not understand them, you will find out when I go through setting this up:

A number

#x#

squared

#x^#

plus two times the number less 7

#x^2 + 2(x-7)#

is equal to zero

#x^2 + 2(x-7) = 0#

I believe this is what you meant.