How do you turn a standard form to vertex form y=x^2-1?

Jun 13, 2016

For the given equation the vertex form is
$\textcolor{w h i t e}{\text{XXX}} y = {\left(x - 0\right)}^{2} + \left(- 1\right)$

Explanation:

The general vertex form is
$\textcolor{w h i t e}{\text{XXX}} y = \textcolor{g r e e n}{m} {\left(x - \textcolor{red}{a}\right)}^{2} + \textcolor{b l u e}{b}$
for a parabola with vertex at $\left(\textcolor{red}{a} , \textcolor{b l u e}{b}\right)$

The given equation: $y = {x}^{2} - 1$
can be converted into an explicit vertex form as
$\textcolor{w h i t e}{\text{XXX")y=color(green)(1)(x-color(red)(0))^2+color(blue)(} \left(- 1\right)}$
with vertex at $\left(\textcolor{red}{0} , \textcolor{b l u e}{- 1}\right)$