How do you turn $y = \frac{1}{2} x - 3$ $y=1/2x -3$ into standard form using integers?

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Answer 1 · 2016-11-20T09:26:51

$x - 2 y = 6$ $x-2y=6$

There is only one denominator which we need to get rid of.

$y = \frac{1}{2} x - 3 \leftarrow$ $y = 1/2x-3" "larr$ multiply through by 2

$2xx y - cancel2 xx 1/cancel2x - 2xx3$

$2y = x-6" "larr$ there are no fractions!

$x-2y =6" "larr$ re-arrange the terms

How do you turn y=1/2x -3y=12x−3y=1/2x -3 into standard form using integers?