How do you find the integral x39x2dx ?

1 Answer
Aug 29, 2014

=(9x2)5253(9x2)32+c, where c is a constant

Explanation :

=x39x2dx

Using Integration by Substitution,

let's assume 9x2=t2, then

2xdx=2tdt xdx=tdt

=(9t2)t2dt

=(t49t2)dt

=t4dt9t2dt

=t559t33+c, where c is a constant

=t553t3+c, where c is a constant

Substituting t back,

=(9x2)5253(9x2)32+c, where c is a constant