# How do you use cross multiplication to solve \frac{2}{x+3}-\frac{1}{x+4}=0?

Nov 4, 2014

$\frac{2}{x + 3} - \frac{1}{x + 4} = 0$

by adding $\frac{1}{x + 4}$,

$\implies \frac{2}{x + 3} = \frac{1}{x + 4}$

by cross multiplication,

$\implies 2 \cdot \left(x + 4\right) = 1 \cdot \left(x + 3\right)$

by multiplying out,

$\implies 2 x + 8 = x + 3$

by subtracting $x$,

$\implies x + 8 = 3$

by subtracting $8$,

$\implies x = - 5$

I hope that this was helpful.