How do you use cross products to solve #s/11=30/110#?

1 Answer
Apr 4, 2017

Answer:

Cross multiply to get #s=3#

Explanation:

Math is Fun

We can use the cross multiplication formula.
Following the image's suggestions, we can plug in #s# for #a#, #11# for #b#, #30# for #c#, and #110# for #d#.

We'd multiply #a# and #d#, and #b# and #c#.

#a*d=s*110# and #b*c=11*30#.

#s*110=110s#, and #11*30=330#.

We'd then set the two values equal to each other: #110s=330#. We'd want to get #s# to its simplest form, so divide both sides by #110#.

#(110s)/ 110=s#, and #330/110=3#, so #s=3#.