# How do you use f (x)= 2x - 3 and g(x)= 1-x^2 to evaluate f(g(0))?

Jan 12, 2017

See the full process for evaluating these functions below.

#### Explanation:

First, evaluate $g \left(0\right)$:

If $g \left(\textcolor{red}{x}\right) = 1 - {x}^{2}$, then

$g \left(\textcolor{red}{0}\right) = 1 - {0}^{2}$

$g \left(\textcolor{red}{0}\right) = 1 - 0$

$g \left(0\right) = 1$

Second, evaluate $f \left(g \left(0\right)\right)$:

If $f \left(\textcolor{red}{x}\right) = 2 x - 3$ and $g \left(0\right) = 1$, then

$f \left(g \left(0\right)\right) = f \left(1\right)$

and

$f \left(\textcolor{red}{1}\right) = \left(2 \times 1\right) - 3$

$f \left(\textcolor{red}{1}\right) = 2 - 3$

$f \left(\textcolor{red}{1}\right) = - 1$

Therefore

$f \left(g \left(0\right)\right) = - 1$