How do you use Heron's formula to find the area of a triangle with sides of lengths #2 #, #5 #, and #5 #?

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Answer 1 · 2016-03-26T05:01:51

#2sqrt6#

#color(blue)(sqrt(s(s-a)(s-b)(s-c))#

Where

#color(red)(a,b,c=sides,s=(a+b+c)/(2)#

#s# is also defined as the Semi-perimeter of the #triangle#

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Values

#color(orange)(a=2#

#color(orange)(b=5#

#color(orange)(c=5#

#color(orange)(s=(2+5+5)/2=12/2=6#

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Start to solve it

#rarrsqrt(6(6-2)(6-5)(6-5))#

#rarrsqrt(6(4)(1)(1))#

#rarrsqrt(6(4))#

#color(green)(rArrsqrt(24)=sqrt(4*6)=2sqrt6~~4.899#