How do you use Heron's formula to find the area of a triangle with sides of lengths $29$ , $21$ , and $22$ ?

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Answer 1 · 2016-01-27T01:21:18

$The Area = 230.04 units^2$

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First we would find S which is the sum of the 3 sides divided by 2.

$S = (29 + 21 + 22)/2$ = $72/2$ = 36

Then use Heron's Equation to calculate the area.

$Area = sqrt(S(S-A)(S-B)(S-C))$

$Area = sqrt(36(36-29)(36-21)(36-22))$

$Area = sqrt(33(7)(15)(14))$

$Area = sqrt(52,920)$

$Area = 230.04 units^2$

How do you use Heron's formula to find the area of a triangle with sides of lengths 29 29 , 21 21 , and 22 22 ?