# How do you use Heron's formula to find the area of a triangle with sides of lengths 12 , 6 , and 11 ?

Area $= 32.83957217 \text{ }$square units

#### Explanation:

let sides $a = 12$ and $b = 6$ and $c = 11$

compute half the perimeter $s = \frac{a + b + c}{2}$

$s = \frac{12 + 6 + 11}{2} = 14.5$

The Heron's Formula for area of the triangle

Area $= \sqrt{s \left(s - a\right) \left(s - b\right) \left(s - c\right)}$

Area $= \sqrt{14.5 \left(14.5 - 12\right) \left(14.5 - 6\right) \left(14.5 - 11\right)}$

Area $= 32.83957217 \text{ }$square units

God bless....I hope the explanation is useful.